Is the function h(u,v)=cos(u)+e^nu+√(sinh(u^2 )+√(v+e^nu )) , Where n is second digit of your arid number for example if your arid number is 19-arid-12345 then choose n=2. Is is continuous? In case of yes then find the points of continuity. Explain briefly
Define h(0,0) in such a way that h is continuous at origin here n=5
h(u,v)=ln((nu^2-u^2 v^2+nv^2)/(u^2+v^2 ))
Is the function h(u,v)=cos(u)+e^nu+√(sinh(u^2 )+√(v+e^nu )), Where n=5 Is is continuous? In case of yes then find the points of continuity. Explain briefly
Improper Integral (Integrals with Infinite Limits)
∫dx/(x^2-2x-3) from 0 to 4
Improper Integral (Integrals with Infinite Limits)
∫dz/(z-1)^(2/3) from 0 to 2
Improper Integral (Integrals with Infinite Limits)
∫dy/√(y-1) from 5 to ∞
Improper Integral (Integrals with Infinite Limits)
∫e^x dx from - ∞ to 1
Improper Integrals (Integrals with Infinite Limits)
∫dt/t^3 from1 to ∞
Integration by Partial Fractions
1.) ∫dt/(1+sint+cost)
2.) ∫dy/(5+4cosy)
Integration by Partial Fractions
1.) ∫dy/(5 secy+4)
2.) ∫dx/(3-5Sin2x) from 0 to π/4