Question

Improper Integrals (Integrals with Infinite Limits)

∫dt/t^3 from1 to ∞

Answer 1

$\int_1^\infin\dfrac{1}{t³}dt = \int_1^\infin t^{-3}dt$

$= [\dfrac{t^{-2}}{-2}]^\infin_1 = [-0.5t^{-2}]^\infin_1$

$= 0-(-0.5(1^{-2}) = 0.5$