Differential Equations Answers

X^2y"+x(x-1) y'+(1-x)y=0 solve by series solution

(x^2+1) y"+xy'-y=0 solve by power series

(x^2+1) y''+xy'-xy=0 in series solution

A curve is such that dy∕dx=√ (2x+5) and (2,5) is a point on the curve. What is the equation of the curve?

Using the method of undetermined coefficients, find the general solution of the differential equation,
y'''' - 2y''' + 2y'' = 3e^(-x) + 2e^(-x)x + e^(-x)sinx.

a curve is such that dy/dx = -x square + 5x - 4.
1) find the x- coordinates of each of the stationary points of the curve.
2) obtain an expression for d square y/d x square (second derivative) and hence or otherwise find the nature of each of the stationary points .
3)given that the curve passes through the point (6 , 2 ), find the equation of the curve .

(y+xz)p-(x+yz)q=x²-y²

Solve: z( p − q )= z^2 +( x + (y ^2))

a uniform chain of length l and mass ml is coiled on the floor and mass mc is attached to one end and projected vertically upward with velocity (2gh)^1÷2 find the height of fall

Solve the differential equation
dy/dx + (x/1-x^2)y = x√y, y(0) = 1.