x²(y-z)p + y²(z − x)q = z²(x-y)
Prove that Pn(1) = 1 and Pn(-1) = (-1)
Solve by method of variation of parameters, (D 4)y 4 tan2x
Evaluate
x^2y^3 + x(
1 + y^2)dy/dx= 0
Find the general solution and the second solution of,
x2y"-3xy'+4y=0,given y1(x)=x2
Solve (d^2y)/(dx^2)+y=sec^2x