d2y/dx2 + d2u/dy2 = 0
0 < x < 2 , 0 < y < 1
u(x, 0) = sin πx , u(x, 1) = x/2
u(0, y) = sin πy , u(2, y) = y
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Expert's answer
2020-12-11T10:59:45-0500
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