Obtain the least-order differential equation x = c1sin (y + c2)?
x=c1sin(y+c2)differentiate both sides with respect to yx′=c1cos(y+c2)differentiate both sides with respect to y againx′′=−c1sin(y+c2)x′′=−xx′′+x=0.x=c_1\sin(y+c_2)\\ \text{differentiate both sides with respect to y}\\ x'=c_1\cos(y+c_2)\\ \text{differentiate both sides with respect to y again}\\ x''=-c_1\sin(y+c_2)\\ x''=-x\\ x''+x=0.x=c1sin(y+c2)differentiate both sides with respect to yx′=c1cos(y+c2)differentiate both sides with respect to y againx′′=−c1sin(y+c2)x′′=−xx′′+x=0.
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