Obtain the least-order differential equation x = c1sin (y + c2)?
"x=c_1\\sin(y+c_2)\\\\\n\\text{differentiate both sides with respect to y}\\\\\nx'=c_1\\cos(y+c_2)\\\\\n\\text{differentiate both sides with respect to y again}\\\\\nx''=-c_1\\sin(y+c_2)\\\\\nx''=-x\\\\\nx''+x=0."
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