The function can be modelled by the equation given by
y=3x2ex3
The Indefinite integral of this equation is:
∫ydx
=∫3x2ex3dx
Let us assume that:
x3=u⇒3x2dx=du
Substituting x3=u into the integration and integrating with respect to du , we have:
=∫eudu
=eu+C [ ∵∫exdx=ex+C (where C is a constant of integration) ]
Undo substitution and we have:
=ex3+C[∵u=x3]
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