As drone's velocity is directed towards the train, it's velocity becomes "(-200 i+100j)m\/s" where north represents positive y-axis and east represents positive x-axis.
Now, as the initial horizontal distance is 1km. It takes the drone "1\/200hr." to cover this distance(y-component of velocity does not affect the motion in x-direction and vice versa).
In this "1\/200hr." the train and the drone travel "(1\/200)*100km=0.5km" in the positive y-direction.
Thus, the drone and train meet each other at a distance of 0.5km from the intersection point.
Comments
Leave a comment