The matrix
"\\left[ \n\\begin{array}{cccc} \n3 & -4 & 2 & 0\\\\\n-9 & 12 & -6 & 0\\\\\n-6 & 8 & -4 & 0\n\\end{array}\n\\right]"
is equivalent to the matrix
"\\left[ \n\\begin{array}{cccc} \n3 & -4 & 2 & 0\\\\\n3 & -4 & 2 & 0\\\\\n3 & -4 & 2 & 0\n\\end{array}\n\\right]" after dividing each element of the second row by -3 and each element of the
third row by -2. The last matrix is equivalent to the matrix
"\\left[ \n\\begin{array}{cccc} \n3 & -4 & 2 & 0\\\\\n0 & 0 & 0 & 0\\\\\n0 & 0 & 0 & 0\n\\end{array}\n\\right]" after subtraction from second and third rows the first row.
Therefore, the system is equivalent to the equation "3x_1-4x_2+2x_3=0" which has the following infinitely many solutions:
"\\begin{cases}\nx_1=\\frac{4}{3}x_2-\\frac{2}{3}x_3\\\\\nx_2\\in\\mathbb R\\\\\nx_3\\in \\mathbb R \n\\end{cases}"
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