A matrix is invertible if its determinant is non-zero.
We will check the determinant of the given matrix:
"\\begin{vmatrix}\n 1 & 1 & 1 \\\\\n 2 & 3 & 0 \\\\\n 3 & 8 & 3 \\\\\n\\end{vmatrix}" = 1"\\begin{vmatrix}\n 3 & 0 \\\\\n 8 & 3\n\\end{vmatrix}" -1"\\begin{vmatrix}\n 2 & 0 \\\\\n 3 & 3\n\\end{vmatrix}" +1"\\begin{vmatrix}\n 2 & 3 \\\\\n 3 & 8\n\\end{vmatrix}" = 1(9)-1(6)+1(7) = 10 which is not equal to zero.
Hence, the given matrix is invertible.
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