u ⃗ = ( 1 , 0 ) , v ⃗ = ( 0 , 1 ) \vec{u}=(1,0),\vec{v}=(0,1) u = ( 1 , 0 ) , v = ( 0 , 1 )
1.1
u ⃗ v ⃗ = ∣ u ⃗ ∣ ∣ v ⃗ ∣ cos θ cos θ = u ⃗ v ⃗ ∣ u ⃗ ∣ ∣ v ⃗ ∣ u ⃗ v ⃗ = 1 ⋅ 0 + 0 ⋅ 1 = 0 cos θ = 0 \vec{u}\vec{v}=|\vec{u}||\vec{v}|\cos\theta\\
\cos\theta=\frac{\vec{u}\vec{v}}{|\vec{u}||\vec{v}|}\\
\vec{u}\vec{v}=1\cdot0+0\cdot1=0\\
\cos\theta=0 u v = ∣ u ∣∣ v ∣ cos θ cos θ = ∣ u ∣∣ v ∣ u v u v = 1 ⋅ 0 + 0 ⋅ 1 = 0 cos θ = 0
1.2
S = ∣ u ⃗ ∣ ∣ v ⃗ ∣ sin θ ∣ u ⃗ ∣ = 1 2 + 0 2 = 1 ∣ v ⃗ ∣ = 0 2 + 1 2 = 1 cos θ = 0 , θ = 9 0 0 S = 1 ⋅ 1 ⋅ sin 9 0 0 = 1 S=|\vec{u}||\vec{v}|\sin\theta\\
|\vec{u}|=\sqrt{1^2+0^2}=1\\
|\vec{v}|=\sqrt{0^2+1^2}=1\\
\cos\theta=0, \theta=90^0\\
S=1\cdot1\cdot\sin90^0=1 S = ∣ u ∣∣ v ∣ sin θ ∣ u ∣ = 1 2 + 0 2 = 1 ∣ v ∣ = 0 2 + 1 2 = 1 cos θ = 0 , θ = 9 0 0 S = 1 ⋅ 1 ⋅ sin 9 0 0 = 1
2.1
L 1 : x = w 0 + s u , s ∈ R w 0 = ( w 00 , w 01 ) , u = ( a , b ) x = w 00 + a s y = w 01 + b s , s ∈ R s = x − w 00 a y = w 01 + b ⋅ x − w 00 a k = b a L 1 : x = w 1 + t v , t ∈ R w 1 = ( w 10 , w 11 ) , v = ( c , d ) x = w 10 + t c y = w 11 + t d , t ∈ R t = x − w 10 c y = w 11 + d ⋅ x − w 10 c k 1 = d c L 1 ∣ ∣ L 2 : k = p k 1 b a = p ⋅ d c L_1:x=w_0+su,s\in R\\
w_0=(w_{00},w_{01}), u=(a,b)\\
x=w_{00}+as\\
y=w_{01}+bs,s\in R\\
s=\frac{x-w_{00}}{a}\\
y=w_{01}+b\cdot\frac{x-w_{00}}{a}\\
k=\frac{b}{a}\\
L_1:x=w_1+tv,t\in R\\
w_1=(w_{10},w_{11}), v=(c,d)\\
x=w_{10}+tc\\
y=w_{11}+td,t\in R\\
t=\frac{x-w_{10}}{c}\\
y=w_{11}+d\cdot\frac{x-w_{10}}{c}\\
k_1=\frac{d}{c}\\
L_1||L_2:\\
k=pk_1\\
\frac{b}{a}=p\cdot\frac{d}{c} L 1 : x = w 0 + s u , s ∈ R w 0 = ( w 00 , w 01 ) , u = ( a , b ) x = w 00 + a s y = w 01 + b s , s ∈ R s = a x − w 00 y = w 01 + b ⋅ a x − w 00 k = a b L 1 : x = w 1 + t v , t ∈ R w 1 = ( w 10 , w 11 ) , v = ( c , d ) x = w 10 + t c y = w 11 + t d , t ∈ R t = c x − w 10 y = w 11 + d ⋅ c x − w 10 k 1 = c d L 1 ∣∣ L 2 : k = p k 1 a b = p ⋅ c d
2.2
α : − 2 x + 4 y − 5 z + 5 = 0 n ⃗ = ( − 2 , 4 , − 5 ) β : A ( 2 , 4 , − 3 ) ∈ β , n ⃗ ∣ ∣ β − 2 ( x − 2 ) + 4 ( y − 4 ) − 5 ( z + 3 ) = 0 − 2 x + 4 y − 5 z − 27 = 0 \alpha:-2x+4y-5z+5=0\\
\vec{n}=(-2,4,-5)\\
\beta: A(2,4,-3)\in \beta, \vec{n}||\beta\\
-2(x-2)+4(y-4)-5(z+3)=0\\
-2x+4y-5z-27=0 α : − 2 x + 4 y − 5 z + 5 = 0 n = ( − 2 , 4 , − 5 ) β : A ( 2 , 4 , − 3 ) ∈ β , n ∣∣ β − 2 ( x − 2 ) + 4 ( y − 4 ) − 5 ( z + 3 ) = 0 − 2 x + 4 y − 5 z − 27 = 0
2.3
α : 2 x − 3 y + 4 z + 7 = 0 n ⃗ = ( 2 , − 3 , 4 ) ⊥ α α ∣ ∣ a , n ⃗ ⊥ a , A ( 2 , 5 , 3 ) ∈ a x − 2 2 = y − 5 − 3 = z − 3 4 \alpha:2x-3y+4z+7=0\\
\vec{n}=(2,-3,4) \bot\alpha\\
\alpha||a, \vec{n}\bot a, A(2,5,3)\in a\\
\frac{x-2}{2}=\frac{y-5}{-3}=\frac{z-3}{4} α : 2 x − 3 y + 4 z + 7 = 0 n = ( 2 , − 3 , 4 ) ⊥ α α ∣∣ a , n ⊥ a , A ( 2 , 5 , 3 ) ∈ a 2 x − 2 = − 3 y − 5 = 4 z − 3
2.4
A ( − 2 , 3 , 4 ) ∈ α a : x − 4 0 − 4 = y + 2 2 + 2 = z − 5 4 − 5 a ⃗ = ( − 4 , 4 , − 1 ) ⊥ α − 4 ( x + 2 ) + 4 ( y − 3 ) − ( z − 4 ) = 0 − 4 x + 4 y − z − 16 = 0 A(-2,3,4)\in \alpha\\
a:\frac{x-4}{0-4}=\frac{y+2}{2+2}=\frac{z-5}{4-5}\\
\vec{a}=(-4,4,-1)\bot\alpha\\
-4(x+2)+4(y-3)-(z-4)=0\\
-4x+4y-z-16=0 A ( − 2 , 3 , 4 ) ∈ α a : 0 − 4 x − 4 = 2 + 2 y + 2 = 4 − 5 z − 5 a = ( − 4 , 4 , − 1 ) ⊥ α − 4 ( x + 2 ) + 4 ( y − 3 ) − ( z − 4 ) = 0 − 4 x + 4 y − z − 16 = 0