Singular matrix :
A n×n square matrix A is a singular matrix if its determinant is zero. In other words, a n×n square matrix is a singular matrix if it does not have an inverse A⁻¹. For example :
Let us take a 2×2 square matrix A as "\\begin{bmatrix}\n 12 & 8 \\\\\n 3 & 2\n\\end{bmatrix}"
Here , determinant of matrix A = 12x2-3x8=0
So , inverse of matrix A i.e. A-1 does not exist.
Hence, A is a singular matrix.
Non- singular matrix :
A n×n square matrix P is a non-singular matrix if its determinant is non-zero. In other words, a n×n square matrix is a non-singular matrix if its inverse P⁻¹ exists. For example :
Let us take a 2×2 square matrix P as "\\begin{bmatrix}\n 10 & 3 \\\\\n 5 & 2\n\\end{bmatrix}"
Here , determinant of matrix P = 10x2-3x5=5 which is not equal to zero.
So , inverse of matrix P i.e. P-1 exists.
Hence, P is a non-singular matrix.
Now , to prove that non-singular matrix must be square:
In the definition itself, a non-singular matrix is a square matrix .
Because if suppose that a matrix A is not a square matrix , then, it is not possible to find the determinant of this matrix A and determine whether the determinant is zero or non-zero to decide its singularity.
Hence , is non- singular matrix is a square matrix .
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