X2uxx +2xyuxy+uyy=u
(Note - nothing is asked in question , so I am giving basic idea to approach these types of problems)
Solution:-
"x^2u_{xx} +2xyu_{xy}+u_{yy}=u"
"On \\ solving \\ we \\ got \\\\"
"A= x^2 \\\\\nB = 2xy \\\\\nC = 1"
Now use
"b^2-4ac =0"
To check it is which type of curve this is
"4x^2y^2 - 4x^2= 0 \\\\\n4x^2(y^2-1)=0"
"\\implies"
"x=0 , y= +1,-1"
After deciding the curve
Also we can find the colonial form.
As several things .
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