These equation cannot be solved by method of reduction of order, for using this method we must have at least one solution of the given equation.
These can be solved by using Method of variation of parameters,
(D2 +1)y = cosec x
The auxiliary equation is (m2+1)=0
m=±i
Therefore complimentary function CF=c1cosx+c2sinx
i.e. =c1f1(x)+c2f2(x)
where
f1(x)=cosx
f2(x)=sinx
f1′(x)=−sinx
f2′(x)=cosx
R=cosec x
f1f2′−f1′f2=cos2x+sin2x=1
P=−∫(f1f2′−f1′f2)f2Rdx
=−∫sinxcosecx dx
=−∫dx
=-x
similarly
Q=∫(f1f2′−f1′f2)f1Rdx
=∫cosxcosecxdx
=∫sinxcosxdx
=∫cotxdx
=log(sin x)
P.I.=Pf1+Qf2
=−xcosx+sinxlog(sinx)
complete solution
y=c.f.+p.I.
=c1cosx+c2sinx−xcosx+sinxlog(sinx)
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