ln(1+x)=Σn=1∞(−1)n−1nxnln(3+4x)=ln(3)+ln(1+(34x))=ln(3)+Σn=1∞(−1)n−1n(34x)n==ln(3)+34x−21(34)2x2+31(34)3x3−41(34)4x4+51(34)5x5+O(x6)T3(x)=ln(3)+34x−98x2+8164x3T4(x)=ln(3)+34x−98x2+8164x3−8164x4T5(x)=ln(3)+34x−98x2+8164x3−8164x4+12151024x5
convergence interval(−43,43]
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