Pythagorean Theorem
L2=x2+1502 Differentiate both sides with respect to t
2L(dtdL)=2x(dtdx) Solve for dtdL
dtdL=(Lx)dtdx Substitute L=x2+1502
dtdL=(x2+1502x)dtdx Given dtdx=20ft/sec
If x=250 ft
dtdL=(2502+1502250)(20)
dtdL=34100 ft/sec≈17.15 ft/s
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