Question #199833

The function f, defined by f(x)= |x-2| is differentiable in [0,1].

True or false with full explanation




1
Expert's answer
2021-05-31T00:10:27-0400

Let us show that the function ff, defined by f(x)=x2f(x)= |x-2| is differentiable in [0,1][0,1]. If x2<0x-2<0, that is x<2x<2, then f(x)=(x2)=x+2.f(x)=-(x-2)=-x+2. In particular, for x[0,1]x\in[0,1] we have that f(x)=x+2.f(x)=-x+2. Since the elementary linear function is differentiable in each point, we conclude that the function ff is differentiable in [0,1][0,1].



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