Answer to Question #199728 in Calculus for Moe

Question #199728

which of the expressions below are equal to


41+74+109+1316...4•1 + 7•4 + 10•9 +13•16...


when summed to the kk terms?


1)

kk

ΣΣ (a3+3a2)(a^3 + 3a^2)

a=1a = 1


2)

kk

ΣΣ (3a1)(a2)(3a-1)(a^2)

a=1a = 1


3)

kk

ΣΣ (3a3+a2)(3a^3 + a^2)

a=1a = 1



4)

k(k+1)(9k2+13k+2)k(k+1)(9k^2 + 13k +2)

_________________________

1212


5)


k(k+1)(9k2+2k+13)k(k+1)(9k^2+2k+13)

___________________________

4


1
Expert's answer
2021-06-07T18:40:37-0400

3)

a=1k(3a3+a2)=a=1k((3a+1)a2)\displaystyle\sum_{a=1}^{k}(3a^3+a^2)=\displaystyle\sum_{a=1}^{k}((3a+1)a^2)

=41+74+109+1316+...(3k+1)k2=4\cdot1+7\cdot4+10\cdot9+13\cdot16+...(3k+1)k^2



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