Given, the expression
3•4•8−5•6•16+7•8•32−... (upto k times).
1)
Σa=3k+1a(a+1)(−1)a+12a=3.4.8−4.5.16+5.6.32−...(upto k +1 terms)
2)
Σa=1k(2a+1)(2a+2)2a+2=3.4.8+5.6.16+7.8.32+...(upto k terms)
3)
Σa=2k+14(−1)aa(2a−1)2a=4.2.3.4−4.3.5.8+4.4.7.16+...(upto k +1 terms)
4)
Σa=3k(−1)aa(a+1)(a+5)=−3.4.8+4.5.9−5.6.10+...(upto k terms)Since, none of the above series matched woth the given series. Therefore, correct option is (5) none of these.
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