3. The distance travelled by a train on a straight track in the first two seconds is given by
π = β«20 20(1βπ^βπ‘)ππ‘20
Find the distance travelled in Metres
"\\mathrm{Take\\:the\\:constant\\:out}:\\quad \\int a\\cdot f\\left(x\\right)dx=a\\cdot \\int f\\left(x\\right)dx"
"=20\\cdot \\int _0^{-2}-1+e^udu"
"\\int _a^bf\\left(x\\right)dx=-\\int _b^af\\left(x\\right)dx,\\:a<b"
"=20\\left(-\\int _{-2}^0-1+e^udu\\right)"
"=20\\left(-\\left(-\\int _{-2}^01du+\\int _{-2}^0e^udu\\right)\\right)"
"=20\\left(-\\left(-2+1-\\frac{1}{e^2}\\right)\\right)"
"=-20\\left(-\\frac{1}{e^2}-1\\right)"
"22.70670"m
Comments
Leave a comment