3. The distance travelled by a train on a straight track in the first two seconds is given by
š = ā«20 20(1āš^āš”)šš”20
Find the distance travelled in Metres
Takeā theā constantā out:ā«aā f(x)dx=aā ā«f(x)dx\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dxTaketheconstantout:ā«aā f(x)dx=aā ā«f(x)dx
=20ā ā«0ā2ā1+eudu=20\cdot \int _0^{-2}-1+e^udu=20ā ā«0ā2āā1+eudu
ā«abf(x)dx=āā«baf(x)dx,ā a<b\int _a^bf\left(x\right)dx=-\int _b^af\left(x\right)dx,\:a<bā«abāf(x)dx=āā«baāf(x)dx,a<b
=20(āā«ā20ā1+eudu)=20\left(-\int _{-2}^0-1+e^udu\right)=20(āā«ā20āā1+eudu)
=20(ā(āā«ā201du+ā«ā20eudu))=20\left(-\left(-\int _{-2}^01du+\int _{-2}^0e^udu\right)\right)=20(ā(āā«ā20ā1du+ā«ā20āeudu))
=20(ā(ā2+1ā1e2))=20\left(-\left(-2+1-\frac{1}{e^2}\right)\right)=20(ā(ā2+1āe21ā))
=ā20(ā1e2ā1)=-20\left(-\frac{1}{e^2}-1\right)=ā20(āe21āā1)
22.7067022.7067022.70670m