Question #199580

3. The distance travelled by a train on a straight track in the first two seconds is given by

š‘ = ∫20 20(1āˆ’š‘’^āˆ’š‘”)š‘‘š‘”20

Find the distance travelled in Metres


Expert's answer

Take the constant out:∫aā‹…f(x)dx=aā‹…āˆ«f(x)dx\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx

=20ā‹…āˆ«0āˆ’2āˆ’1+eudu=20\cdot \int _0^{-2}-1+e^udu

∫abf(x)dx=āˆ’āˆ«baf(x)dx, a<b\int _a^bf\left(x\right)dx=-\int _b^af\left(x\right)dx,\:a<b

=20(āˆ’āˆ«āˆ’20āˆ’1+eudu)=20\left(-\int _{-2}^0-1+e^udu\right)

=20(āˆ’(āˆ’āˆ«āˆ’201du+āˆ«āˆ’20eudu))=20\left(-\left(-\int _{-2}^01du+\int _{-2}^0e^udu\right)\right)

=20(āˆ’(āˆ’2+1āˆ’1e2))=20\left(-\left(-2+1-\frac{1}{e^2}\right)\right)

=āˆ’20(āˆ’1e2āˆ’1)=-20\left(-\frac{1}{e^2}-1\right)

22.7067022.70670m


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