Answer to Question #178352 in Calculus for Phyroe

Question #178352

Integration Procedures (Integration by Parts)


∫csc^(-2)x dx


1
Expert's answer
2021-04-29T16:56:23-0400

I=csc2xdx=sin2xdx=cosxsinxI=\int{csc^{-2}x}dx=\int{sin^2x dx}=-\cos{x}\sin{x}-


(cosx)cosxdx=-\int{(-\cos{x})\cos{x}dx}=


=cosxsinx+cos2xdx==-\cos{x}\sin{x}+\int{\cos^2{x}dx}=


=cosxsinx+(1sin2x)dx==-\cos{x}\sin{x}+\int{(1-\sin^2{x})dx}=


=cosxsinx+xsin2xdx==-\cos{x}\sin{x}+x-\int{\sin^2{x}dx}=


=cosxsinx+xI=-\cos{x}\sin{x}+x-I


2I=cosxsinx+x2I=-\cos{x}\sin{x}+x


I=12(xcosxsinx)I=\frac{1}{2}(x-\cos{x}\sin{x})



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment