Answer to Question #178350 in Calculus for Phyroe

Question #178350

Integration Procedures (Integration by Parts)


∫ y √(y+1)dy


1
Expert's answer
2021-04-25T07:22:33-0400

So, the solution is (integration by parts):


"\\int y \\sqrt{y+1} dy = \\int y \\sqrt{y+1} d(y+1) = \\\\\n\\int y d(\\frac{2}{3}(y+1)^{\\frac{3}{2}}) = \\frac{2}{3}y(y+1)^{\\frac{3}{2}} - \\\\\n- \\int \\frac{2}{3}(y+1)^{\\frac{3}{2}} d(y+1) = \\frac{2}{3}y(y+1)^{\\frac{3}{2}} - \\\\\n- \\frac{2}{3} \\frac{2}{5} (y+1)^{\\frac{5}{2}} + const = \\frac{2}{3}(y+1)^{\\frac{3}{2}} \\cdot \\\\\n\\cdot [y - \\frac{2}{5}(y+1) +const = \\frac{2}{15}(y+1)^{\\frac{3}{2}}[3y-2] + \\\\\n+ const"




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS