Answer to Question #178003 in Calculus for Charles

Question #178003

Simplify (9.0×10^9)[20×10^-8/d+0.1)-5.0×10^-8/d^2)=0


1
Expert's answer
2021-04-15T07:27:18-0400

9x109(20x108d5x108d2)=09x10^9(\frac{20x10^{-8}}{d}-\frac{5x10^{-8}}{d^2)}=0

9x109(20x108d5x108d2)=09x10^9(\frac{20x10^{-8}d-5x10^{-8}}{d^2})=0

9x109(5x108(4d1)d2)=09x10^9(\frac{5x10^{-8}(4d-1)}{d^2})=0

(450(4d1)d2)=0(\frac{450(4d-1)}{d^2})=0

4d1=04d-1=0

d=0.25


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