Answer to Question #178003 in Calculus for Charles

Question

Simplify (9.0×10^9)[20×10^-8/d+0.1)-5.0×10^-8/d^2)=0

Answer 1

$9x10^9(\frac{20x10^{-8}}{d}-\frac{5x10^{-8}}{d^2)}=0$

$9x10^9(\frac{20x10^{-8}d-5x10^{-8}}{d^2})=0$

$9x10^9(\frac{5x10^{-8}(4d-1)}{d^2})=0$

$(\frac{450(4d-1)}{d^2})=0$

$4d-1=0$

d=0.25