1∫22∫30∫18xyzdzdxdy=
81∫22∫30∫1xyzdzdxdy=
81∫22∫3⎣⎡0∫1xyzdz⎦⎤dxdy=
81∫22∫3⎣⎡xy0∫1zdz⎦⎤dxdy=
81∫22∫3xy⎣⎡0∫1zdz⎦⎤dxdy=
81∫22∫3xy[2z2]01dxdy=
81∫22∫3xy[212−202]dxdy=
81∫22∫3xy⋅21dxdy=
8⋅211∫22∫3xydxdy=
41∫2⎣⎡2∫3xydx⎦⎤dy=
41∫2⎣⎡y2∫3xdx⎦⎤dy=
41∫2y⎣⎡2∫3xdx⎦⎤dy=
41∫2y[2x2]23dy=
41∫2y[232−222]dy=
41∫2y[29−4]dy=
41∫2y⋅25dy=
4⋅251∫2ydy=
101∫2ydy=
10[2y2]12=
10⋅[222−212]=
10⋅24−1=
10⋅23= 15
Answer:
1∫22∫30∫18xyzdzdxdy=15
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