Question

Differentiate the following function:g(x)= x³+(1/x³)

Answer 1

Solution.

$$g(x)= x^3+\frac{1}{x^3}$$

$g'(x)=3x^2-3x^{-4}=3x^2-\frac{3}{x^4}. \newline$

Derivatives in this expression are calculated using the formula:

$$(x^n)'=n\cdot x^{n-1}.$$

Answer. $g'(x)=3x^2-\frac{3}{x^4}.$