y = x³+ 3 x + x³x
y=x3+3x+x3xy=x^3+3x+x^3xy=x3+3x+x3x
⟹ y=x4+x3+3x\implies y=x^4+x^3+3x⟹y=x4+x3+3x
Slope at any point (y1,x1)(y_1,x_1)(y1,x1) is given by,
(dydx)(x1,y1)=d(x4+x3+3x)dx(x1,y1)(\frac{dy}{dx})_{(x_1,y_1)}=\frac{d(x^4+x^3+3x)}{dx}_{(x_1,y_1)}(dxdy)(x1,y1)=dxd(x4+x3+3x)(x1,y1)
=(4x3+3x2+3)x1,y1=(4x^3+3x^2+3)_{x_1,y_1}=(4x3+3x2+3)x1,y1
=4x13+3x12+3=4x_1^3+3x_1^2+3=4x13+3x12+3
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