y = x³+ 3 x + x³x
"y=x^3+3x+x^3x"
"\\implies y=x^4+x^3+3x"
Slope at any point "(y_1,x_1)" is given by,
"(\\frac{dy}{dx})_{(x_1,y_1)}=\\frac{d(x^4+x^3+3x)}{dx}_{(x_1,y_1)}"
"=(4x^3+3x^2+3)_{x_1,y_1}"
"=4x_1^3+3x_1^2+3"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment