Question #164070

The marketing research department for a company that manufactures and sells computers established the following price-demand and cost functions. p(x)=2262-63x   where p(x) is the wholesale price per computer in dollars at which x thousands of computers can be soldC(x)=4151+599xwhere C(x) is the cost in thousands of dollars. Domain of both functions is 0≤x≤35. 1. Find the Maximum Revenue (in thousands of dollars) RMax(x)=
(Round to 3 d.p.)

1
Expert's answer
2021-02-24T12:39:55-0500

R(x)=x(p(x))=x(226263x)=2262x63x2R(x)=x(p(x))=x(2262-63x)=2262x-63x^2

ddx(2262x63x2)=0\frac{d}{dx}(2262x-63x^2)=0

226263x=02262-63x=0

x=2262126x=\frac{-2262}{-126}

x=17.9523809523817.952x=17.95238095238\approx17.952

Rmaxx17.952 thousands of dollarsR_{max}x\approx17.952 \space thousands\space of\space dollars


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