Question #162718

Prove that a sequence that diverges to +∞ (resp. −∞) is divergent according

to the previous definition.



Expert's answer

Solution:

We say that lim⁡n→∞an=∞\lim _{n \rightarrow \infty} a_{n}=\infty if for every number M>0 there is an integer N such that an>M whenever n>Na_{n}>M \quad \text { whenever } \quad n>N .

Next, we say that lim⁡n→∞an=−∞\lim _{n \rightarrow \infty} a_{n}=-\infty if for every number M<0 there is an integer N such thatan<M whenever n>Na_{n}<M \quad \text{ whenever }\quad n>N .

According to the above definition, we have the following:

If lim⁡n→∞an\lim _{n \rightarrow \infty} a_{n} doesn't exist or is infinite we say the sequence diverges. Note that we will say the sequence diverges to ∞\infty if lim⁡n→∞an=∞\lim _{n \rightarrow \infty} a_{n}=\infty or divergent.

Also, lim⁡n→∞an=−∞\lim _{n \rightarrow \infty} a_{n}=-\infty we will say that the sequence diverges to −∞-\infty or divergent.


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