Question #162656

Find the vertical and horizontal asymptotes of the graph of f(x)=3x+1/x^2-4. plot the graph of function and asymptotes


Expert's answer

f(x)=3x+1x24Vertical assymtote:x24=0x=±2limxf(x)=limx3x+1x24=limx3x+1x214x2=0Horizontal assymtote:y=0\displaystyle f(x) = \frac{3x + 1}{x^2 - 4} \\ \textsf{Vertical assymtote}:\,\, x^2 - 4 = 0\\ x = \pm 2 \\ \begin{aligned} \lim_{x \to \infty} f(x) &= \lim_{x \to \infty}\frac{3x + 1}{x^2 - 4}\\ &= \lim_{x \to \infty}\frac{\frac{3}{x} + \frac{1}{x^2}}{1 - \frac{4}{x^2}} &= 0 \end{aligned} \\ \textsf{Horizontal assymtote}:\,\, y = 0\\


LATEST TUTORIALS
APPROVED BY CLIENTS