f(x)=x∗ex
f′(x)=ex+x∗ex
f−1(x)−inverse function f(x)
(f−1(x))′=f′(f−1(x))1
f−1(x):x=y∗ey
x=y∗ey−this function does not allow you to explicitly express y in x
x≈y∗(1+y)
y≈2−1+1+4∗x
f−1(0.5)≈0.37
(f−1(0.5))′=f′(0.37)1=e0.37+0.37∗e0.371≈0.504
Answer:0.504
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