Evaluate the ∫e^z (sq rt of 1+e^z) dz
Solution.
"\\int e^z\\sqrt{1+e^z}dz."Make a replacement:
"t=\\sqrt{1+e^z}, t\\geq0," from here "t^2=1+e^z, \\text{then }\n2tdt=e^zdz."
We will have
"\\int t\\cdot 2tdt=\\int 2t^2dt=\\newline=\n2\\frac{t^3}{3}+C=\n\\frac{2}{3}(1+e^z)^{\\frac{3}{2}}+C."
Answer.
"\\frac{2}{3}(1+e^z)^{\\frac{3}{2}}+C."
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