Evaluate the integral of e^(5x)dx
I = ∫\int∫ e5x dxdxdx
We know that,
∫\int∫ e(ax) dxdxdx = eaxddx(ax)\dfrac{e^{ax}}{\dfrac{d}{dx}(ax)}dxd(ax)eax + C = eaxa\dfrac{e^{ax}}{a}aeax + C
On comparing this formula with our question, we find that
a = 5
So, I = ∫\int∫ e5x dxdxdx = e5x5\dfrac{e^{5x}}{5}5e5x + C
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