Question #162047

Evaluate the integral of e^(5x)dx


Expert's answer

I = \int e5x dxdx


We know that,

\int e(ax) dxdx = eaxddx(ax)\dfrac{e^{ax}}{\dfrac{d}{dx}(ax)} + C = eaxa\dfrac{e^{ax}}{a} + C

On comparing this formula with our question, we find that

a = 5


So, I = \int e5x dxdx = e5x5\dfrac{e^{5x}}{5} + C


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