Evaluate the integral of e^(5x)dx
I = "\\int" e5x "dx"
We know that,
"\\int" e(ax) "dx" = "\\dfrac{e^{ax}}{\\dfrac{d}{dx}(ax)}" + C = "\\dfrac{e^{ax}}{a}" + C
On comparing this formula with our question, we find that
a = 5
So, I = "\\int" e5x "dx" = "\\dfrac{e^{5x}}{5}" + C
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