Question #162019

Evaluate the ∫(1-1/x)² dx


Expert's answer

Solution.

(11x)2dx=\int(1-\frac{1}{x})^2dx=(12x+1x2)dx=\int(1-\frac{2}{x}+\frac{1}{x^2})dx=1dx21xdx+1x2dx=\int1dx-2\int\frac{1}{x}dx+\int\frac{1}{x^2}dx=x2lnx+x11+C=x-2\ln{|x|}+\frac{x^{-1}}{-1}+C=x2lnx1x+C,x-2\ln{|x|}-\frac{1}{x}+C,

where CC is some constant.

Answer. x2lnx1x+C.x-2\ln{|x|}-\frac{1}{x}+C.



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