Evaluate the ∫(1-1/x)² dx
Solution.
"\\int(1-\\frac{1}{x})^2dx=""\\int(1-\\frac{2}{x}+\\frac{1}{x^2})dx=""\\int1dx-2\\int\\frac{1}{x}dx+\\int\\frac{1}{x^2}dx=""x-2\\ln{|x|}+\\frac{x^{-1}}{-1}+C=""x-2\\ln{|x|}-\\frac{1}{x}+C,"where "C" is some constant.
Answer. "x-2\\ln{|x|}-\\frac{1}{x}+C."
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