Evaluate the ∫y(y²-2)²dy
Solution
∫y(y²-2)²dy = (1/2) ∫(y²-2)²dy2
Substitution x = y2 => ∫y(y²-2)²dy = (1/2) ∫(x-2)²dx = (1/2) ∫(x-2)² d(x-2) = (x-2)3 /6 + C = (y2-2)3 /6 + C
Answer
∫y(y²-2)²dy = (y2-2)3 /6 + C
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