y=x+x+xWe apply chain rule while differentiatingdxdy=dxd(x+x+x)We know that dxd(g(x))=2g(x)1dxd(g(x))So, we havedxdy=dxd(x+x+x)=2x+x+x1dxd(x+x+x)=2x+x+x1(1+2x+x1dxd(x+x))=2x+x+x1(1+2x+x1(1+2x1))
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