Given,
Local atmospheric pressure (P)=101.3kPa
Absolute pressure at the point A=?
The density of the air (ρair)=1.2kg/m3
The density of the mercury (ρhg)=13600kg/m3
Specific gravity of oil (goil)=0.85
Pgas−Po=ρgh
Pgas=Po+ρgh
Pgas=Po+g(ρoilhoil+ρhgh−ρairhair)
Now, substituting the values,
Pgas=101.3kPa+9.8(0.0254)(13600×6+1000×27−1.25×25)
=27126kP
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