Answer to Question #190486 in Mechanics | Relativity for April

Question

A man of mass 65 kg stands on a solid floating on water. If the solid has a density of 0.6 g/cm3

and the man standing on it is just barely out of the surface of the water, determine the volume of

the solid.

Answer 1

Here when man is standing on solid floating on water.

Then water would be remove due to man,

So Volume of solid = Volume of man

As the mass of solid is negligible compared to mass of man

So,

$$Volume \ of\ solid=\dfrac{mass}{density}$$

Here, M = 65 kg (as the mass of solid is negligible)

Density $\rho=0.6\ g/cm^3=600\ kg/m^3$

$\therefore \text{Volume of solid}=\dfrac{65}{600}=0.1083\ m^3$

Hence the volume of the solid is equivalent to 0.1083 m$^3$