Answer to Question #190485 in Mechanics | Relativity for April

Question

Ice has a density of 0.92 g/cm3 and seawater has a density of 1.04 g/cm3

. Determine the total

volume of a floating iceberg if 30 m3

is above the seawater

Answer 1

We have given that,

Density of ice = $0.92g/cm^3$

Density of Sea water = $1.04 g/cm^3$

Volume of iceberg above sea water = $30m^3$

Let v be the volume of iceberg immersed in water

As per the law of floatation, $\dfrac{v}{V} = \dfrac{Density \hspace{3mm}of\hspace{3mm} ice }{Density\hspace{3mm} of \hspace{2mm} sea \hspace{3mm}water}$

$\dfrac{v}{V} = \dfrac{0.92}{1.04} = 0.88$

$v = 0.88V$

Volume of the iceberg over the surface of sea water is given by:

$V(1-0.88) = 30$

$v = \dfrac{300}{0.12}$

$v = 250m^3$