Answer to Question #190358 in Mechanics | Relativity for Adane

Question #190358

an object moving at 15m/s slows uniformly at the rate of 3m/s each second for a time of 2 sec..determine final velocity average velocity and distance moved


1
Expert's answer
2021-05-09T15:08:22-0400

Gives

u=15m/secu=15m/sec

acceleration (a)=31m/sec2-\frac{3}{1} m/sec^2

acceleration (a)=-3m/sec2m/sec^2

Time(t)=2sec

Final velocity

v=u+atv=u+at

v=153×2v=15-3\times2


v=9m/secv=9m/sec

Distance move

s=ut+12at2s=ut+\frac{1}{2}at^2

s=15×2+12(3)×22s=15\times2+\frac{1}{2}(-3)\times2^2

s=24 m


average velocity

Vave=displacementtime\frac{displacement}{time}

vave=24020=12m/sec\frac{24-0}{2-0}=12m/sec


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