Answer to Question #190482 in Mechanics | Relativity for April

Question

A hydraulic press has a small piston of diameter 2 cm. If a force of 60 N is applied to the smaller

piston, a force of 3000 N is exerted on the larger piston. What is the diameter of the larger piston?

Answer 1

By pascal's law we can say that pressure inside , the external static pressure applied on a confined liquid is distributed or transmitted evenly through out the liquid in all direction.

P₁ = P₂

=

$\dfrac{F_1}{A_1}$ $= \dfrac{F_2}{A_2}$

=

$\dfrac{60}{{\pi}r_1^{2}}=$ $\dfrac{3000}{{\pi}r_2^{2}}$ .....1)

where r_{1 ,} r₂ are respectively radius of smaller and larger piston .

r₁ = 1 cm

Putting the values in equation 1)

$r_2^{2}$ =$\dfrac{3000}{60}=50$

$r_2=7.07\ cm.$