Question

A car moving with a constant speed of 55.0km/hr completes a circular track in 7.50 minutes. Calculate the magnitude of the acceleration of the car.

Answer 1

To be given in quest ion

Car speed=55km/h=$\frac{275}{18}m/sec$

Time (t)=7.50 minutes=450sec

Circuler motion

$a_{c}=\frac{v^2}{r}\rightarrow(1)$

$T=\frac{2\pi r}{v}\rightarrow(2)$

eqution (1);(2) we can written as

$a_{c}=\frac{v^2}{{\frac{vT}{2\pi}}}\rightarrow(3)$

$a_{c}=\frac{2πv}{T}\rightarrow(4)$

Put value

$a_{c}=\frac{2π\times\frac{275}{18}}{450}=0.213m/sec^2$