A car moving with a constant speed of 55.0km/hr completes a circular track in 7.50 minutes. Calculate the magnitude of the acceleration of the car.
To be given in quest ion
Car speed=55km/h="\\frac{275}{18}m\/sec"
Time (t)=7.50 minutes=450sec
Circuler motion
"a_{c}=\\frac{v^2}{r}\\rightarrow(1)"
"T=\\frac{2\\pi r}{v}\\rightarrow(2)"
eqution (1);(2) we can written as
"a_{c}=\\frac{v^2}{{\\frac{vT}{2\\pi}}}\\rightarrow(3)"
"a_{c}=\\frac{2\u03c0v}{T}\\rightarrow(4)"
Put value
"a_{c}=\\frac{2\u03c0\\times\\frac{275}{18}}{450}=0.213m\/sec^2"
Comments
Leave a comment