Question

An elastic wire with the undistorted length of L0= 80cm and the elastic constant k= 150 N/m is cut in half, L0' = 40cm. Under the action of a deforming force, F=6N is lengthened by how much?

Answer 1

$F=k\Delta x,\implies$

$\Delta x=\frac Fk,$

$\Delta x=\frac{6}{150}=4~cm.$