How much would the equivalent
resistance in a parallel circuit be if it had a 3Ω, a
6 Ω, a 5 Ω, and a 2 Ω resistor?
R1=3ΩR2=6ΩR3=5ΩR4=2ΩR_1=3\Omega\\R_2=6\Omega\\R_3=5\Omega\\R_4=2\OmegaR1=3ΩR2=6ΩR3=5ΩR4=2Ω
⇒1Req=1R1+1R2+1R3+1R4\\\Rightarrow\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\dfrac{1}{R_4}⇒Req1=R11+R21+R31+R41
⇒1Req=13+16+15+12\Rightarrow\dfrac{1}{R_{eq}}=\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{5}+\dfrac{1}{2}⇒Req1=31+61+51+21
⇒1Req=10+5+6+1530\Rightarrow\dfrac{1}{R_{eq}}=\dfrac{10+5+6+15}{30}⇒Req1=3010+5+6+15
⇒Req=3036=0.833 Ω\Rightarrow R_{eq}=\dfrac{30}{36}=0.833\space\Omega⇒Req=3630=0.833 Ω
Req = 0.833 Ω\OmegaΩ
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