For a compound circuit R series with XL , R = 3 omega and XL = 6O omega connected with parallel branches R = 2 omega and XC = 8 omega E=30V angle 0^ Find source (IT) .
I=EZ1+Z2I=\frac{E}{Z_1+Z_2}I=Z1+Z2E
Z1=R12+XL12=32+602=60.07 ΩZ_1=\sqrt{R_1^2+X^2_{L1}}=\sqrt{3^2+60^2}=60.07\ \OmegaZ1=R12+XL12=32+602=60.07 Ω
1Z2=1R22+1XC22=122+182=178 1/Ω\frac{1}{Z_2}=\sqrt{\frac{1}{R_2^2}+\frac{1}{X_{C2}^2}}=\sqrt{\frac{1}{2^2}+\frac{1}{8^2}}=\frac{\sqrt{17}}{8} \ 1/\OmegaZ21=R221+XC221=221+821=817 1/Ω
Z2=8/17=1.94 ΩZ_2=8/\sqrt{17}=1.94\ \OmegaZ2=8/17=1.94 Ω
I=3060.07+1.94=0.48 AI=\frac{30}{60.07+1.94}=0.48\ AI=60.07+1.9430=0.48 A
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