Question

Find the current for a series circuit with R = 30 using complex algebra v= 15sin(wt + 10 degrees)

Answer 1

$V_{max}=15\space V$

$R=30\Omega\\I_{max}=\dfrac{V_{max}}{R}=\dfrac{15}{30}=0.5\space A$

$I=0.5sin(\omega t+10\degree)$