Answer to Question #178953 in Electric Circuits for WEAM

Question

A a series circuit consists of resistor R = 3 XC =5 Omega,XL =9 Omega with a voltage source of E=50V angle O^ and f = 60Hz , Find the reactive power for the capacitor

Answer 1

$R=3\Omega$

$X_c=5\Omega\\X_L=9\Omega$

Total impedance of the circuit$(Z)$ = $\sqrt{R^2+(X_L-X_c)^2}=\sqrt{9+16}=5\Omega$

$V_{RMS}=50V$

$I_{RMS}=\dfrac{V_{RMS}}{Z}=\dfrac{50}{5}=10\space A$

Reactive Power = $I_{RMS}^2Z=100\times5=500\space VAR$