Question #312714

1.   The height of grade 1 pupils is approximately normally distributed with µ = 45 inches and s = 2.

a. If an individual pupil is selected at random, what is the probability that he or she has a height of 42 and 47?

b. A class of 30 of these pupils is used as a sample. What is the probability that the class mean is between 42 and 47?

c.  If a pupil is selected at random, what is the probability that is taller than 46 inches?

d. A class of 30 of these pupils is used as sample. What is the probability that the class mean is greater than 46 inches?





1
Expert's answer
2022-03-19T02:40:38-0400

Population mean μ=45~\mu=45

Standard deviation σ=2~\sigma=2


(a) P(42 and 47)P(42~and~47)

Z=XμσZ=\dfrac{X-\mu}{\sigma}

Z42=42452=1.5Z_{42}=\dfrac{42-45}{2}=-1.5

P42=0.06681P_{42}=0.06681

Z47=47452=1.0Z_{47}=\dfrac{47-45}{2}=1.0


P47=10.84134P_{47}=1-0.84134


P47=0.15866P_{47}=0.15866


=0.06681  and  0.15866=0.06681 ~~and~~0.15866


(b) P(42<Xˉ<47)P(42<\bar X<47)


=P(42452<Z<47452)=P(\frac{42-45}{2}<Z<\frac{47-45}{2})


=P(1.5<Z<1.0)=P(-1.5<Z<1.0)


=P(Z<1.0)P(Z<1.5)=P(Z<1.0)-P(Z<-1.5)


=0.77453=0.77453


(c) P(X>46)=P(Z>46452)P(X>46)=P(Z>\frac{46-45}{2})


=P(Z>0.5)=P(Z>0.5)


=1P(Z<0.5)=1-P(Z<0.5)


=0.30854=0.30854


(d) P(Xˉ>46)=P(Z>46452)P(\bar X>46)=P(Z>\frac{46-45}{2})


=P(Z>0.5)=P(Z>0.5)


=1P(Z<0.5)=1-P(Z<0.5)


=0.30854=0.30854



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