A die is thrown 5 times. What is the probability of obtaining a 4 or 5?
A. Zero
B. Once
C. Twice
Hint: Calculate the p(4 or 5) for a single throw
The probability of a single throw is
p=26=13p=\frac{2}{6}=\frac{1}{3}p=62=31
Then
A:P=(1−p)5=(23)5=32243B:P=5p(1−p)4=5⋅13(23)4=80243C:P=C52p2(1−p)3=10⋅(13)2(23)3=80243A:P=\left( 1-p \right) ^5=\left( \frac{2}{3} \right) ^5=\frac{32}{243}\\B:P=5p\left( 1-p \right) ^4=5\cdot \frac{1}{3}\left( \frac{2}{3} \right) ^4=\frac{80}{243}\\C:P=C_{5}^{2}p^2\left( 1-p \right) ^3=10\cdot \left( \frac{1}{3} \right) ^2\left( \frac{2}{3} \right) ^3=\frac{80}{243}A:P=(1−p)5=(32)5=24332B:P=5p(1−p)4=5⋅31(32)4=24380C:P=C52p2(1−p)3=10⋅(31)2(32)3=24380
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