1. The height of grade 1 pupils is approximately normally distributed with µ = 45 inches and s = 2.
1. If an individual pupil is selected at random, what is the probability that he or she has a height of 42 and 47?
X ~ N(45,22)N(45, 2^2)N(45,22)
P(42<X<47)=P(42<N(45,22)<47)=P(42<45+2N(0,1)<47)==P(−1.5<N(0,1)<1)=P(N(0,1),1)<1)−P(N(0,1)<−1.5)==0.84134−0.06681=0.77453P(42<X<47)=P(42<N(45,2^2)<47)=P(42<45+2N(0,1)<47)=\\=P(-1.5<N(0,1)<1)=P(N(0,1),1)<1)-P(N(0,1)<-1.5)=\\=0.84134-0.06681=0.77453P(42<X<47)=P(42<N(45,22)<47)=P(42<45+2N(0,1)<47)==P(−1.5<N(0,1)<1)=P(N(0,1),1)<1)−P(N(0,1)<−1.5)==0.84134−0.06681=0.77453
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