f(x)=ex+x−4 a=0,b=2
f(a)=f(0)=e0+0−4=−3
f(b)=f(2)=e2+2−4=e2−2
f(a)f(b)=f(0)f(2)=−3(e2−2)<0
xn=2an+bn an+1=xn,bn+1=bn,f(an)f(xn)≥0
an+1=an,bn+1=xn,f(bn)f(xn)≥0
∣f(xn)∣≤ε=>answer=xn
n01234567891011xn11.51.251.1251.06251.093751.0781251.07031251.074218751.0722656251.07324218751.07373046875f(xn)−0.281718171.98689070.740342960.20521685−0.043904060.079198540.01728845−0.013396800.00192349−0.00574223−0.001910770.00000601
∣∣1.07324218751.07373046875−1.0732421875∣∣⋅100%≈
≈0.0455%<0.05% Root is 1.07373046875
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